Biol1107 Unit 4: Genetics 23)M and N blood group in humans is determined by a si

Question

Biol1107 Unit 4: Genetics 23)M and N blood group in humans is determined by a single co- Blood Type Number dominant gene. You examine the blood groups present in an isolated population and obtain the results shown at the right. a) What is the frequency of the M allele for the gene? M 285 225 490 1000 MN b) What is the frequency of the N allele for the gene? 24)You are examining a population that is in Hardy-Weinberg equilibrium for gene A. a) For a gene to be in Hardy-Weinberg equilibrium in a population, what conditions must be met? Explain why defying any of these conditions would result in a population NOT being in Hardy-Weinberg equilibrium. b)

Explanation / Answer

23)A frequency of M allele =285@0 =0.285.

Frequency of allele is, calculated by counting the number of times an allele occur in a population and divided by total number of occurrence of all the alleles.

23)B Frequency of N allele =225@0 =0.225

24)A

If Hardy Weinberg equilibrium is achieved then no evolution occur.

1)Population must be very large

2)Population must be isolated from other populations.

3)No mutation

4)Random mating

5)No natural selection.

24)B

Hardy weinberg equation is p2+2pq+q2=1

If the frequencies of allele M and N in a population are given by 'p' and 'q' and the frequency of MN allele is 'pq'.

So, p2=0.081,q2=0.240,2pq=0.275

P2+2pq+q2=1 (put the values in Hardy weinberg equation)

0.081+0.275+0.210=0599

Not equals to 1

So, this population not accepted by Hardy weinberg equilibrium .

Means frequency of allele may be change in the population.

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