Please help using simple terms.. Next, think about how videos are posted and sha

Question

Please help using simple terms..

Next, think about how videos are posted and shared online. First, examine an unpopular video on a single social medium. Suppose that, on the very first day of this video was posted, it received its highest quantity of views. As the days go on, the video receives fewer and fewer each day. Create an exponential function that models the number of views the video gets each day. Determine for yourself the number of times the video was initially viewed on its first day, or its initial value, and decide on a daily decay facto. All rights reserved. less than one. Now graph the function and make sure to track its number of daily views over a one-month period. You will submit the following. a. an unpopular video function b. an unpopular video graph 5. Look at a popular video. Create another exponential function with a smaller initial value (i.e., the number of times the video was viewed on its first day), but this time, with a growth factor that is greater than one. Graph the popular video function and make sure to show its number of daily views over a one-month period. What are the differences in the functions and the behavior of the graphs between the popular and the unpopular videos? You will submit the following. a. a popular video function b. a popular video graph c. a comparison of the unpopular video to the popular video 6. What are some factors that you did not consider in your model that could influence the spread of a viral electronic media? Write a brief paragraph that describes some additional factors that you could take into account, and how that might change the behavior of the function and graph. You will submit the following. a. a brief paragraph

Explanation / Answer

The exponential equation is of the form

V(t) = V0(1 -r)t

where V0 is the number of views on the first day

Suppose a video is posted which was viewed 100,000 on the first day

Therefore V0=100,000 and the function is

V(t)=100000(1-r)t

And suppose number of views after 10th day =10

10=100,000(1-r)10

10/100,000=(1-r)10

(1/10,000)1/10=1-r

.3981=1-r

r=1-.3981

r=.6019=60.19%

Therefore rate of decay=60.19%

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.