Two consecutive odd numbers are such that three times the first is 107 more than

Question

Two consecutive odd numbers are such that three times the first is 107 more than twice the second. What are those two odd numbers?
Please define your variables and write the equation you used as a part of the solution. Use algebra to solve the problem. Solutions that involve trial-and-error will not earn credit.

Here is a similar problem:

Two consecutive odd numbers are such that three times the first is 5 more than twice the second. What are those two odd numbers?

Defining the variable:

Suppose the first number is x.

Then the second number must be (x+2).

Setting up the equation:

3x = 5+2(x+2)

Solving the equation:

3x = 5+2(x+2)

Þ 3x = 5+2x+4

Þ 3x-2x = 9

Þ x = 9

Ans: The numbers are 9 and 11.

Explanation / Answer

Given that

Two consecutive odd numbers are such that three times the first is 107 more than twice the second

Let first number = x

Second number = x + 2

   3x = 107 + 2(x + 2)

3x = 107 + 2x + 4

3x - 2x = 111

x = 111

x + 2 = 111 + 2

= 113

Therefore ,

The numbers are 111 and 113

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