A 30-second commercial during Super Bowl XXXIX in 2005 cost advertisers 2.4 mill

Question

A 30-second commercial during Super Bowl XXXIX in 2005 cost advertisers 2.4 million. For the first Super Bowl in 1967, an advertiser could have purchased approximately 26.19 minutes of advertising time for the same amount of money. Assuming that advertising cost is proportional to its length of time, find the cost of advertising, in dollars/second, during the 2005 Super Bowl. Cost = dollars/second. Assuming that advertising cost is proportional to its length of time, find the cost of advertising, in dollars/second, during the 1967 Super Bowl. Cost = dollars/second. How many times more expensive was Super Bowl advertising in 2005 than in 1967? times more expensive.

Explanation / Answer

a) In 2005 Cost in dollars per second = 2.4/30 = 0.08 million dollars/sec = 80000 $/ sec

b) In 1967 Cost in dollars per second = 2.4/26.19*60 = 0.001527 million dollar/sec = 1527.3 $/sec

c) the advertsising cost in 2005 was 80000/1527.3 = 52.38 times more expensive than in 1967

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