Compute the discriminant. Then determine the number and type x^2 + 4x + 3 = 0 -2

Question

Compute the discriminant. Then determine the number and type x^2 + 4x + 3 = 0 -28; two complex imaginary solutions 4; two unequal real solutions 0; one real solution Compute the discriminant. Then determine the number and type x^2 + 12x + 36 = 0 -144 two complex imaginary solutions 144; two unequal real solutions 0; one real solution Find all values of x satisfying the given conditions. y = x^2 + 8x and y = 4 2 Squareroot 5 plusminus 4 a. -4 plusminus 2 Squareroot 5 plusminus 2 Squareroot 5 -4 plusminus 2 Squareroot 10

Explanation / Answer

10.

for ax^2 + bx + c = 0,

discriminant is given by:

D = b^2 - 4ac

x^2 + 4x + 3 = 0

D = 4^2 - 4*1*3 = 4

Since D > 0 two unequal real solutions.

11.

x^2 + 12x + 36 = 0

D = 12^2 - 4*1*36

D = 144 - 144 = 0

Since D = 0, So only one real solution.

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