Compute the coefficients for the most accurate (in the sense of satisfying as ma
ID: 3583771 • Letter: C
Question
Compute the coefficients for the most accurate (in the sense of satisfying as many exactness constraints as possible explicit linear multi-step formulas for which alpha_0 = 1, alpha_1 = -1, and alpha_3 = ... = alpha_k = 0. Compute the coefficients for k = 1, 2, 3, 4. What power of delta t is LTE proportional to for k = 1, 2, 3, 4? Compute the coefficients for the most accurate (in the sense of satisfying as many exactness constraints as possible) implicit linear multi-step formulas for which alpha_0 = 1, alpha_1 = -1, and alpha_3 = ... = alpha_k = 0. Compute the coefficients for k = 1, 2, 3, 4. What power of delta t is LTE proportional to for k = 1, 2, 3, 4? Compute the coefficients for the most accurate (in the sense of satisfying as many exactness constraints as possible) implicit linear multi-step formulas for which alpha_0 = 1, and beta_1 = ... = beta_k = 0. Compute the coefficients for k = 1, 2, 3, 4. What power of delta t is LTE proportional to for k = 1, 2, 3, 4?Explanation / Answer
A)
explicit linear multistep:
In the established notation we have k = 1, 0 = 1, 1 = 1. The terms similarly come from the coefficients on the right hand side
Now
Here k = 1
so that 1yn+1 + 0yn = h(1fn+1 + 0fn)
substituting the values in for the coefficients gives
yn+1 yn = h.
B)
Implicit linear multistep:
k = 1, 0 = 1, 1 = 1.
Here k = 1
so that 1yn+1 + 0yn = h(1fn+1 + 0fn)
substituting the values in for the coefficients gives
yn+1 yn = h.
C)
Implicit linear multistep:
k = 1, 0 = 1,0 = 1 and k = 0
Here k = 1
we have 1yn+1 + 0yn = h(1fn+1 + 0fn).
substituting the values in for the coefficients gives
yn = hfn.
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