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Compute the coefficients for the most accurate (in the sense of satisfying as ma

ID: 3583771 • Letter: C

Question

Compute the coefficients for the most accurate (in the sense of satisfying as many exactness constraints as possible explicit linear multi-step formulas for which alpha_0 = 1, alpha_1 = -1, and alpha_3 = ... = alpha_k = 0. Compute the coefficients for k = 1, 2, 3, 4. What power of delta t is LTE proportional to for k = 1, 2, 3, 4? Compute the coefficients for the most accurate (in the sense of satisfying as many exactness constraints as possible) implicit linear multi-step formulas for which alpha_0 = 1, alpha_1 = -1, and alpha_3 = ... = alpha_k = 0. Compute the coefficients for k = 1, 2, 3, 4. What power of delta t is LTE proportional to for k = 1, 2, 3, 4? Compute the coefficients for the most accurate (in the sense of satisfying as many exactness constraints as possible) implicit linear multi-step formulas for which alpha_0 = 1, and beta_1 = ... = beta_k = 0. Compute the coefficients for k = 1, 2, 3, 4. What power of delta t is LTE proportional to for k = 1, 2, 3, 4?

Explanation / Answer

A)

explicit linear multistep:

In the established notation we have k = 1, 0 = 1, 1 = 1. The terms similarly come from the coefficients on the right hand side

Now

Here k = 1

so that 1yn+1 + 0yn = h(1fn+1 + 0fn)

substituting the values in for the coefficients gives

yn+1 yn = h.

B)

Implicit linear multistep:

k = 1, 0 = 1, 1 = 1.

Here k = 1

so that 1yn+1 + 0yn = h(1fn+1 + 0fn)

substituting the values in for the coefficients gives

yn+1 yn = h.

C)

Implicit linear multistep:

k = 1, 0 = 1,0 = 1 and k = 0

Here k = 1

we have 1yn+1 + 0yn = h(1fn+1 + 0fn).

substituting the values in for the coefficients gives

yn = hfn.

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