an urn contains 5 red, 4 white, and 6 blue marbles. two marbles are drawn at ran

Question

an urn contains 5 red, 4 white, and 6 blue marbles. two marbles are drawn at random, without replacement.
What is the probability that:
A) a red marble is drawn and then a white B) a white marble is drawn, and then a red marble C) a red or white marble is drawn (in either order) D) the second marble is white, give that the first marble drawn is white E) the first marble drawn is white, given that the second marble drawn is white an urn contains 5 red, 4 white, and 6 blue marbles. two marbles are drawn at random, without replacement.
What is the probability that:
A) a red marble is drawn and then a white B) a white marble is drawn, and then a red marble C) a red or white marble is drawn (in either order) D) the second marble is white, give that the first marble drawn is white E) the first marble drawn is white, given that the second marble drawn is white an urn contains 5 red, 4 white, and 6 blue marbles. two marbles are drawn at random, without replacement.
What is the probability that:
A) a red marble is drawn and then a white B) a white marble is drawn, and then a red marble C) a red or white marble is drawn (in either order) D) the second marble is white, give that the first marble drawn is white E) the first marble drawn is white, given that the second marble drawn is white

Explanation / Answer

Total marbles = 15

a)P( Red and White) = 5 * 4/ [15*14] = 2/21

b) White and red = 4*5/210=2/21

c) Red or white ( in either order) = 2/21+2/21=4/21

d) Second white if first is white = 3white remaining/14 total remaining = 3/14

e) Second is white, so first can be choses in 3 ways for white to come. Probability = 3/14

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