110miuIR. Seclon 3.3 Homework Score: 0 of 1 pt | 17 of 18 (16 complete) HW Score

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110miuIR. Seclon 3.3 Homework Score: 0 of 1 pt | 17 of 18 (16 complete) HW Score: 88 89%, 16 of 18p 3.3.26 Question Help From a box containing 6 black balls and 4 green balls, 3 balls are drawn in succession, each ball being replaced in the box before the probability distribution for the number of green balls. next draw is made. Find the Denote by X the number of green bals in the three draws. Complete the probabilily distibution (Type integers or simplified fractions.) Enter your answer in the edit fields and then click Check Answer Check Answer Clear All All parts showing

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Ans:

There are 6 black and 4 green balls.

Total balls=10

Probability of drawing a green ball=p=4/10=0.4

Now,as each ball is replaced before next draw is made,so event of drawing each ball are independent of each other and also probability of drawing a green ball at each draw remains same,hence we can consider x having a binomial distribution with n=3 and p=0.4

So,

P(x=k)=3Ck*0.4k*0.63-k

where, k=0,1,2,3

x p(x) fractions 0 0.216 216/1000 1 0.432 432/1000 2 0.288 288/1000 3 0.064 64/1000

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