The Human Resources (HR) group gives job applicants at a firm a personality test

Question

The Human Resources (HR) group gives job applicants at a firm a personality test to assess how well they will fit into the firm and get along with colleagues. Historically, test scores have been normally distributed with mean and standard deviation =21. The HR group wants to hire applicants whose true personality rating is greater than 222 points. (Test scores are an imperfect measure of true personality.) Use this information to answer parts a through c below.

a.) Before seeing test results, should the null hypothesis of the HR group assert that for an applicant is greater than 222 or less than 222?

correct answer : mu less than or equal to 222

b.) If the HR group chooses the null hypothesis found in part a, then for what test scores (approximately) will the HR group reject H0 if =5%?

correct answer: HR group will reject for test scores greater than 257

c.) What is the chance for a Type II error using the procedure in part b, if the true score of an applicant is 236?

???? please help me to solve for this part c.)

Explanation / Answer

at 0.05 level critical z =1.645

for rejection region =mean +z*Std deviation =222+1.645*21 =256.542

if mean is 236 and

type II error =P(X<256.542) =P(Z<(256.542-236)/21) =P(Z<0.9782)=0.8360

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.