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According to a guide, 47% of cell phone users have only one cell number, 30% hav

ID: 3043207 • Letter: A

Question

According to a guide, 47% of cell phone users have only one cell number, 30% have two numbers, 10% have three numbers, and 13% have four or more numbers. An independent survey of 964 randomly selected cell phone users found that 476 pay for only one number, 331 pay for two numbers, 114 pay for three numbers, and 31 pay for four or more numbers. Conduct a test to determine if the data from the independent survey contradict the percentages reported by the guide. Use =0.1

Determine the null and alternative hypotheses for this test. Choose the correct answer below.

A. Upper H 0 : p1=47%, p2=30%, p3=10%, p4=13% Upper H Subscript a Baseline :Ha: At least one of the multinomial probabilities does not equal its hypothesized value.

B. Upper H 0 : p2p3p4 Upper H Subscript a Baseline :Ha: At least one of the multinomial probabilities equals its hypothesized value.

C. Upper H 0 :p1=p2=p3=p4 Upper H Subscript a Baseline :Ha: p 1 not equals p 2 not equals p 3 not equals p 4p1p2p3p4

Now find the test statistic.

2equals=

Determine the p-value.

Choose the correct conclusion below.

Fail to reject Upper H 0H0. There is sufficient evidence that the data from the survey contradict the percentages reported by the guide.

Reject Upper H 0H0. There is sufficient evidence that the data from the survey contradict the percentages reported by the guide.

Fail to reject Upper H 0H0. There is insufficient evidence that the data from the survey contradict the percentages reported by the guide.

Reject Upper H 0H0. There is insufficient evidence that the data from the survey contradict the percentages reported by the guide

Explanation / Answer

Answer:

According to a guide, 47% of cell phone users have only one cell number, 30% have two numbers, 10% have three numbers, and 13% have four or more numbers. An independent survey of 964 randomly selected cell phone users found that 476 pay for only one number, 331 pay for two numbers, 114 pay for three numbers, and 31 pay for four or more numbers. Conduct a test to determine if the data from the independent survey contradict the percentages reported by the guide. Use =0.1

Determine the null and alternative hypotheses for this test. Choose the correct answer below.

Answer: A. Upper H 0 : p1=47%, p2=30%, p3=10%, p4=13% Upper H Subscript a Baseline :Ha: At least one of the multinomial probabilities does not equal its hypothesized value.

B. Upper H 0 : p2p3p4 Upper H Subscript a Baseline :Ha: At least one of the multinomial probabilities equals its hypothesized value.

C. Upper H 0 :p1=p2=p3=p4 Upper H Subscript a Baseline :Ha: p 1 not equals p 2 not equals p 3 not equals p 4p1p2p3p4

Now find the test statistic.

2equals=82.278

Determine the p-value. P=0.0000

Choose the correct conclusion below.

Fail to reject Upper H 0H0. There is sufficient evidence that the data from the survey contradict the percentages reported by the guide.

Answer: Reject Upper H0. There is sufficient evidence that the data from the survey contradict the percentages reported by the guide.

Fail to reject Upper H 0H0. There is insufficient evidence that the data from the survey contradict the percentages reported by the guide.

Reject Upper H 0H0. There is insufficient evidence that the data from the survey contradict the percentages reported by the guide

Total sample size is 952

Goodness of Fit Test

observed

expected

O - E

(O - E)² / E

476

447.440

28.560

1.823

331

285.600

45.400

7.217

114

95.200

18.800

3.713

31

123.760

-92.760

69.525

Total

952

952.000

82.278

82.278

chi-square

3

df

0.0000

p-value

Goodness of Fit Test

observed

expected

O - E

(O - E)² / E

476

447.440

28.560

1.823

331

285.600

45.400

7.217

114

95.200

18.800

3.713

31

123.760

-92.760

69.525

Total

952

952.000

82.278

82.278

chi-square

3

df

0.0000

p-value

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