Left-handed People: The table below shows the results of a survey of 1000 people

Question

Left-handed People: The table below shows the results of a survey of 1000 people. The table is bivariate. Gender and dominant hand are the two variables surveyed. A person is selected at random from the sample. Find the probability of each event. GENDER Dominant Hand Men Left Right Total Total 113 462 1425 887 525 475 1000 1·The person is left-handed. 2·The person is left-handed or a man. 3. The person is a right-handed woman. 4. The person is left-handed, given that the person is a man. 5. The person is a woman, given that the person is right-handed.

Explanation / Answer

Ans:

1)P(left handed)=113/1000=0.113

2)P(left handed or man)=P(left handed)+P(man)-P(left handed and man)

=0.113+0.525-0.063=0.575

3)P(right handed and woman)=425/1000=0.425

4)P(left handed/man)=P(left handed and man)/P(man)=0.063/0.525=0.12

5)P(woman/right handed)=P(woman and right handed)/P(right handed)=0.425/0.887=0.4791

Dominant Men Women Total Left 63 50 113 Right 462 425 887 Total 525 475 1000 Joint prob. Distribution Dominant Men Women Total Left 0.063 0.05 0.113 Right 0.462 0.425 0.887 Total 0.525 0.475 1

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