1, what is the particular z value so that the middle 98% of the area under the s
ID: 3046525 • Letter: 1
Question
1, what is the particular z value so that the middle 98% of the area under the standard normal curve is between - and ? (In other words, find the particular value zo such that P(-2o 0.98.) 2. Suppose a random sample of 44 UF students' IQ exam scores had a sample average of 108 points. It is known that the population standard deviation of IQ exam scores is 15 points. Find a 98% confidence interval for the mean UF students' IQ exam score, Justify the relevant confidence interval conditions are met. 3. In order to estimate the proportion of UF students who love their math classes, you use a random sample with 50 students. The sample proportion showed 0.65 of sampled students loved their math class. Find a 95% confidence interval for the proportion of UF students who love their math class. Justify the relevant confidence interval conditions are met.Explanation / Answer
#1.
0.98/2 = 0.49
Hence on each side of the mean there is 0.49 area.
Use standard z-table to find the value of z which represents the 0.49 area
This z value is 2.33
Hence, P(-2.33 < z < 2.33) = 0.98
#2.
mean = 108, sigma = 15 n = 44
#3.
CI for 98% n 44 mean 108 z-value of 98% CI 2.3263 std. dev. 15 SE = std.dev./sqrt(n) 2.26134 ME = z*SE 5.26065 Lower Limit = Mean - ME 102.73935 Upper Limit = Mean + ME 113.26065 98% CI (102.7393 , 113.2607 )Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.