Bes t Selbbio Probability Problems STA2023 OUTOF CLASS ASSIGNMENT Assume you hav
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Bes t Selbbio Probability Problems STA2023 OUTOF CLASS ASSIGNMENT Assume you have a fair deck of playing cards 1. What is the probability of drawing a lack from a full deck of playing cards? probabmty of drawing an Ace? robability of selecting a Queen followed by a Oueenhoma 2. With the Jack out of the deck, what is the Comb 3. What is the p deck?n. 10 it 10 it 59 it 20 12 i of 750 Students FL Central FL South FL State 218 37 Pe 10 ac 255 Total 4. Pfstudent) is form Central FL is?-Zoo-. 5Plsophmore)- 160 152 203 190 132 0-1 s 6HNorthwest FL or Northeast FL)- 3aa0 30 + -6 8. P(Senior and Senior)o 9. P(Out of State and Sophmore5o0 10, p(Foreign)- 3¾oco 11. Roll two dice and find p(total 7) 12. Roll 3 dice and find p(total 3)- 13. How many possible outcomes possible for roll of 2 dice? 14. Roll two dice, what is probability of 3 or 4 or 5 or 6? 5. Roll 3 dice, list outcomes to make a total of 10.Explanation / Answer
(11) When we roll 2 dice the total number of outcomes = 62 = 36
Total number of favourable outcomes to get a sum of 7 = (1,6), (6,1), (2,5), (5,2), (3,4), (4,3) = 6 outcomes.
The required probability = 6/36 = 1/6
(12) When we roll 2 dice the total number of outcomes = 63 = 216
Total number of favourable outcomes to get a sum of 3 = (1,1,1) = 1 outcome
The required probability = 1/216
(13) For a roll of 2 dice, the total outcomes = 36 (The rule is 6n, where n is the number of dice)
(14) Total outcomes = 36.
Favourable outcomes for 3 = (1,2), (2,1) = 2
Favourable outcomes for 4 = (1,3), (2,2), (3,1) = 3
Favourable outcomes for 5 = (1,4), (4,1), (2,3), (3,2) = 4
Favourable outcomes for 6 = (1,5), (5,1), (2,4), (4,2), (3,3) = 5
Total favourable outcomes = 14
Required probability = 14/36 = 7/18
15) To get a total of 10
= (1,3,6), (1,6,3), (3,6,1), (3,1,6), (6,1,3), (6,3,1),(1,4,5), (1,5,4), (4,5,1), (4,1,5), (5,1,4), (5,4,1),
(2,3,5), (2,5,3), (3,5,1), (3,1,5), (5,1,3), (5,3,1), (2,4,4), (4,2,4), (4,4,2),(2,2,6), (2,6,2), (6,2,2),(3,3,4), (3,4,3), (4,3,3)
= 27 outcomes
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