Suppose GRE Quantitative scores are normally distributed with a mean of 582 and

Question

Suppose GRE Quantitative scores are normally distributed with a mean of 582 and a standard deviation of 149. A university plans to recruit students whose scores are in the top 9%. What is the minimum score required for recruitment? Round your answer to the nearest whole number, if necessary.

Answer

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Explanation / Answer

z score corresponding to top 9% of the area = 1.34

Hence,

Minimum score required for recruitment = 582 + 1.34*149 = 782 [Rounded off to nearest whole number]

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