I need help with Discrete Mathematical Structures Chapter 3.4, Problem 36E. Do n

Question

I need help with Discrete Mathematical Structures Chapter 3.4, Problem 36E. Do note that there is already a solution to this problem on this site in the textbook solutions section, but i honestly cannot understand this because of the broken. I am hoping someone with. if it needed i add the question below:

Each day five secretaries draw numbers to determine the order in which they will take their breaks.

(a) What is the probability that today’s order is exactly the same as yesterday’s order?

(b) What is the probability that in today’s order four secretaries have the same position as they had yesterday?

(c) What is the probability that at least one secretary has the same position as yesterday?

Explanation / Answer

a) Probability that today’s order is exactly the same as yesterday’s order= 1/5! = 1/240

b) If four secretaries have the same position, 5th will also have the same position. Probability = 1/5!=1/120

c)probability that at least one secretary has the same position as yesterday=1-P( no secretary) = 1- [4!/5!]=1/5

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