in a relay event, four swimmers swim 100 yards, each Swimmer Mean SD (backstroke
ID: 3048634 • Letter: I
Question
in a relay event, four swimmers swim 100 yards, each Swimmer Mean SD (backstroke) 50 09 0.28 2 (breaststroke) 54 29 023 using a different stroke. A college team looks at the times for the swimmers and creates a model based on the assumptions that the swimmers' performances are each swimmer's times follow a norma model, and the means and standard deviations of the times in seconds are as shown in the table. Complete parts a) and b). 3 (butterfly) 48 97 022 4 (freestyle) 4425 0.18 a) What are the mean and the standard deviation for the relay team's total time in this event? : 197.6 (Round to two decimal places as needed.) b) The team's best time so far this season was 3 17.44 (That's 197 44 seconds.) What is the probability that they will beat that time in the next event? The probability that they will beat that time in the next event is (Round to four decimal places as needed.)Explanation / Answer
a)here mean =(50.09+54.29+48.97+44.25)=197.6
std deviation =(0.282+0.232+0.222+0.182)1/2 =0.46
b)
as 3:17:44 (197.44 seconds)therefore probability of beating it
( please try 0.3632 if above does not work due to rounding error)
for normal distribution z score =(X-)/ here mean= = 197.600 std deviation == 0.4600Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.