5. A researcher is interested in determining if the model used for the distribut

Question

5. A researcher is interested in determining if the model used for the distribution of main economic concerns in the year 2003 for residents in a certain county can still be used in the year 2004. A sample of 370 residents from that county was surveyed in 2004. The following table displays the model for the distribution of economic concerns for the year 2003 and the observed number of sampled respondents in the survey for the same economic concerns for the year 2004. Economic concern I: Jobs 2: Medical care 3: Higher 5% 25 4: Housing Total education 27% 116 32% 91 Model from 2003 36% 138 100% 370 Counts in 2004 Let pi,p. ps, and ps be the proportion of all residents in this county who would list each of the economic concerns as priority for the year 2004. What would be the null hypothesis for a chi-square test for testing if the model from the previous year can still be used? B) HO:P1-25; P2 = 138; p-1 16, p.-91 C) Ho: pi-0.05: p2 0.36; p-0.27;ps 0.32 D) This cannot be determined from the information given. 6·There was a wonderful study conducted in 1898 by von Bortkiewicz, which provides data on the death of soldiers in the Prussian army from kicks by horses and mules. The data pertain to 10 army corps, each observed over 20 years, for a total of 200 corps- years. The following table summarizes the observed data. Note that 109 corps-years had 0 deaths and 65 corps-years had 1 death, etc. eaths Total urrences 109 Von Bortkiewicz felt that a distribution known as the Poisson distribution would describe these data well. Using that distribution, he produced the following probabilities ths Total robabilities 0543 0.3310.101 0.021 0.003 0.999 Under the null hypothesis that the observed cell counts follow the specified distribution, what is the expected number of corps-years in which one death occurred due to horse or mule kicks? A) 66.3 B) 65.0 C) 33.1 D) 40 E) None of the above

Explanation / Answer

5) here option C is correct

6) here as we know that expected frequency =probability *total count =0.331*200=66.2

option A is correct

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