Can someone help me with letter d × × / @ Do Homework-Kevin C Pearson\'s MyLab &

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Can someone help me with letter d

× × / @ Do Homework-Kevin C Pearson's MyLab & Mas. My.UTEP C secure https://www.mathxl.com/Student/PlayerHomework.aspx?homeworkId=470425015&questionid;=7 Stat 2480 Spring 1:30(TR) Homework: Hw5-Ch5 Score: 0 of 5 pts 5.4.62 12 of 12 The results for a blood test for a certain disease are shown a. Estimate the probability that the sickness occurs b. Find the estimated ) sensitivity, (i) specificity d. Explain how the probabi Find the estimated ( P(YesIPOS), (ü) P(NO NEG) d. Explain how the probabilities in parts b and c give four ways of describing the probability that a diagnost agive four wars of descibing the probability tha a diagnostic test makes a coret decisia a. The probability is approximately 0088 (Round to four decimal places as needed ) b. () The sensitivity is approximately 81 (Round to four decimal places as needed) 25 (i) The specificity is approximately 7373 Round to four decimal places as needed) c. 0 P/Yes POS- 0269 (Round to four decimal places as needed) (ü) P(NoINEG)-9977 (Round to four decimal places as needed) d. Describe the probabilities below The probability in b-i is that lone would not have the disease if the test is negative. The probability in b-ii is that one would not have the disease if the test is negative The probability in c-i is that the test would be negative if one does not have the disease The probability in ceis that the test would be positive if one has the disease Click to select your answer's) and then click Check Answer Ci

Explanation / Answer

Solution :

d)

i) Sensitivity :Probability that, if you truly have the disease, the diagnostic test will catch it(correct decision).That is if one would have disease ,test is positive.

ii)Specificity :Probability that, if you truly do not have the disease, the diagnostic test will register negative(correct decision).That is if one does not have disease ,test is negative.

iii)P(Yes|Pos) = Probability that one would have disease given that test results are positive.

iv)P(No|Neg) = Probability that one does not have disease given that test result is negative.

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