No We often use sampling in conjunction with deciding the quality of entire ship

Question

No We often use sampling in conjunction with deciding the quality of entire shipments. Suppose a shipment of 400 components contains 68 defective and 332 non-defective computer components. From the shipment you take a random sample of 25. When sampling with replacement (so that the p = probability of success does not change), note that a success in this case is selecting a defective part. See instructions below to analyze this situation these are only example questions and the quiz will not be identical to these questions: Exactly two defective components in the sample of 25. Two or more defective components in the sample of 25. . Three or less defective components in the sample of 25. . Between one and three (inclusive) defective components. .What are the mean and variance of this discrete random variable? .More than 4 defective components To analyze this situation, follow the procedure we have used in class to generate both the individual and cumulative binomial probabilities for this situation. The write-up above is all you need to generate these tables. You should also have the calculations for the mean and variance of a binomial probability mass function (PMF). Go to the fx (symbol for function). If you need to search, choose the category Statistical and the function you want is BINOM.DIST. See Figure 1 below. When you have chosen BINOM.DIST; you will get your data entry screen (Function Argument). . ee Figure 2 below and you are ready to go.

Explanation / Answer

Here' the answer to the question. Write back in case of doubts:

p = 68/400 = .17

p^ = 1-p = 1-.17 = .83

Sample size = 25

This is a binomial distribution, with sample size = 25

We reject the entire shipment if X>5

So, P(X>5) = 1-P(X<=5) = 1-P(X=0,1..5)

= 1- ( 25C0(.17^0)(.83^17) + ...+25C5(.17^5)(.83^20) )

= 1-0.7575

= .2425

Answer is A.

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