2:51 PM AT&T; LTE Data-2018-01-Spring. CAP-3-Bon… Class Project Sheet2 Sleep 15

Question

2:51 PM AT&T; LTE Data-2018-01-Spring. CAP-3-Bon… Class Project Sheet2 Sleep 15 30 Work Text 300 Live 7 Yes 7 Yes 4 Yes 4 Yes 8 Yes 7 No 5 Yes 4.5 Yes 8 Yes 6 Yes 6.5 Yes 6.75 Yes 7 No 6 Yes 6.75 No 5 Yes 8 Yes 6 No 6 No 6 Yes 7 No 8 Yes 5 Yes 8 No 12 No 6 Yes Campus Campus Campus Commuter Commuter Commuter Commuter Commuter Commuter Campus Campus Campus Campus Campus Campus Commuter Commuter Commuter Commuter Commuter Commuter Commuter Commuter Commuter Campus Campus Commuter Campus Commuter 25 18 35 0 28 20 25 0 0 0 7Yes- 10 Yes 40

Explanation / Answer

Here we have given that dataset of MAT115 students.

We have to test different hypothesis.

1) Here we have to test hypothesis related to variable sleep.

Hypothesis for the test is,

H0 : mu = 6.5 Vs H1 : mu not= 6.5

where mu is population mean hours sleep per night.

Here sample data is given and sample size is too small so we use one sample.t-test.

The test statistic is,

t = (Xbar - mu) / (s/sqrt(n))

sample mean (Xbar ) = 6.71

population mean (mu) = 6.50

standard deviation (s) = 1.68

sample size (n) = 29

t = (6.71 - 6.50) / (1.68/sqrt(29))

t = 0.67

Now we have to find p-value for taking decision.

P-value we can find in EXCEL.

syntax :

=TDIST(x, deg_freedom, tails)

x is absolute value of test statistic.

deg_freedoms = n-1 = 29-1 = 28

tails = 2

P-value = 0.5083

Accept H0 at 5% level of significance.

Conclusion : There is not sufficient evidence to say that the number of hours a night carlow students sleep differ from 6.5.

2) Here work is the variable.

Hypothesis for the test is,

H0 : mu = 19 hour Vs H1 : mu not= 19 hours

where mu is population mean of students work hours a week.

Assume alpha = 0.05

Given that,

population standard deviation (sigma) = 8

Sample mean (xbar) = 15.45

sample size(n) = 29

Here population standard deviation is known so we use one sample z-test.

The test statistic is,

Z = (Xbar - mu) / (sigma / sqrt(n))

= (15.45 - 19) / (8 / sqrt(29))

Z = -2.39

Now we have to find P-value for taking decision.

P-value we can find in excel.

syntax :

=2*NORSMDIST(z)

where z is test statistic.

P-value = 0.01681

P-value < alpha

Reject H0 at 5% level of significance.

Conclusion :

There is sufficient evidence to say that the number of hours Carlow students work a week differ from 19.

Related Questions

Navigate

• Browse (All)
• Browse 2
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.