5. 0/4 points | Previcus Answers My NotesAsk Your Teacher You are taking a multi
ID: 3052583 • Letter: 5
Question
5. 0/4 points | Previcus Answers My NotesAsk Your Teacher You are taking a multiple-choice test with 4 questions. For each question there are 4 different answers: A, B, C, and D. You forgot to study for the test so you are just going to guess the answers. (a) You will guess an answer for each of the 4 questions. In how many different ways could you fill out the answer sheet? 15761x (b) Your teacher gives you the option of leaving any (or all) of questions unanswered if you are unsure of the answer. In how many different ways can you fill out the answer sheet if you have the option of leaving as many questions as you like unanswered? No Resp Notes O Ask Your Teacher 6. 3/4.5 points | Previous Answers (a) Anna's husband is making her a burger. He asks her if she wants her burger with or without cheese. How many options does Anna have? (b) Charlie buys a hot dog from a street vendor. For no extra charge he can choose to have his hot dog with or without onions, and with or without relish. How many options does Charlie have? (c) Ed is going to order a pizza. His local pizza shop has a special which allows him to choose from among 6 different toppings. He can choose as many of these 6 toppings as he likes. How many different options does Ed have?Explanation / Answer
Question 6 )
a )
There are 4 question.
and for each question you have 4 objects (the 4 answer options, a, b, c, and d)
You are going to chose a group of 4, and the order matters (your answer to question #1 is independent of your choice on #3)
Repetition is allowed (you can answer "c" on all of the questions if you want to)
This is a simple permutation.
Use the formula: n^r
where n is the number of objects (the number of answer choices a,b,c,d)
and r is the number of objects you will choose (4 question, one answer for each question)
To solve: 4^4 = 256
That is here total number of ways could you fill out answer sheet 256 ways.
b ) there are four posibility that,
1 question unanswer or 2 question unanswer or 3 question answer or all question unanswer
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Question 6 )
c ) Here Ed have 6 topping and he want to choose a topping from 6 different topping .
here use combination as 6C1 = 6! / (1! ) * (6 - 1)! = 6! / 5! = 6*5! /5! = 6
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