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7) For a certain? candy, 20?% of the pieces are? yellow, 20?% are? red, 15?% are

ID: 3053383 • Letter: 7

Question

7) For a certain? candy, 20?% of the pieces are? yellow, 20?% are? red, 15?% are? blue, 20?% are? green, and the rest are brown. ?A) If you pick a piece at? random, what is the probability that it is? brown?

B) it is yellow or? blue?

C) it is not? green? it is? striped? ?

D Assume you have an infinite supply of these candy pieces from which to draw. If you pick three pieces in a? row, what is the probability that they are all? brown?

E) the third one is the first one that is? red?

F) none are? yellow?

G) at least one is? green?

Explanation / Answer

P(yellow) = 0.2
P(red) = 0.2
P(blue) = 0.15
P(green) =0.2

A) P(brown) = 1 – P(yellow)-P(red)-P(blue)-P(green)
                        = 1-0.2-0.2-0.15-0.2 = 0.25

B) P(yellow or blue) = P(yellow) + P(blue)
                                    = 0.2+0.15 = 0.35

C) P(not green) = 1-P(green) = 1-0.2 = 0.8

D) P(all are brown) = P(brown in first pick)*P(brown in second pick)*P(brown in third pick) [since infinite supply is there, we treat this as WR case which means the draws are independent.]
                                  = 0.25*0.25*0.25 = 0.015625

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