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4. /1.42 points JKEStat11 4.E.124 My Notes A box contains 28 parts, of which 5 a

ID: 3058904 • Letter: 4

Question

4. /1.42 points JKEStat11 4.E.124 My Notes A box contains 28 parts, of which 5 are defective and 23 are nondefective. 2 parts are selected without replacement. (a) Find the probability P(both are defective). (Give your answer correct to two decimal places.) (b) Find the probability P(exactly one is defective). (Give your answer correct to two decimal places.) (c) Find the probability P(neither is defective). (Give your answer correct to two decimal places.) 5. 0.35/1.42 points | Previous Answers My Notes Calculate the combinations by TI-83 calculator. 3 choose 2 = 30 choose 2 = 50 choose 3 = 14 choose 3 = x

Explanation / Answer

4. /1.42 points JKEStat11 4.E.124 My Notes A box contains 28 parts, of which 5 are defective and 23 are nondefective. 2 parts are selected without replacement. (a) Find the probability P(both are defective). (Give your answer correct to two decimal places.) (b) Find the probability P(exactly one is defective). (Give your answer correct to two decimal places.) (c) Find the probability P(neither is defective). (Give your answer correct to two decimal places.) 5. 0.35/1.42 points | Previous Answers My Notes Calculate the combinations by TI-83 calculator. 3 choose 2 = 30 choose 2 = 50 choose 3 = 14 choose 3 = x

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