Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Suppose that a safety group surveyed 1,400 d vers Among those surveyed, 65% said

ID: 3060008 • Letter: S

Question

Suppose that a safety group surveyed 1,400 d vers Among those surveyed, 65% said that careless or aggressive driving was the b est threat on the road, and 26% said that cell phone usage by other drivers was the driving behavior that annoyed them the most. Based on these data and assuming that the sample was a simple random sample, construct and interpret a 9 confidence interval estimate for the true proportion n the population o all dn ors who are annoved by cell phone users The confidence interval estimate is [-- Round to three decimal places as needed. Use ascending order) Interpret the confidence interval estimate O A. There is a 0 90 probability that the sample proportion of drivers who are annoyed by cel phone users is n the interval B. There is 90% confidence that the population proportion of drivers who are annoyed by cell phone users is n the interval C. There is a 0.90 probabity that the population proportion of drivers who are annoyed by cell phone users is in the interval 0 D. There is 90% confidence that the populaton proporton of drivers who are annoyed by cel phone users is equal to one of the bounds of the interval

Explanation / Answer

confidence interval =0.241 to 0.279

interpretation: option b is correct

sample size n                    = 1400 sample proportion     p x/n= 0.2600 std error       =Se            =(p*(1-p)/n) = 0.0117 for 90 % CI value of z= 1.6449 margin of error E=z*std error                            = 0.019 lower confidence bound=sample proportion-margin of error 0.241 Upper confidence bound=sample proportion+margin of error 0.279
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote