interquartile range 541.5 . variance 1011611.1 . standard deviation 1005.7888 me

Question

             interquartile range      541.5       

            . variance          1011611.1                   

            . standard deviation      1005.7888        

             mean          642.41667

            . median       253.5   

            . mode

            . midrange      4040

Discuss the relevance of each statistic to your data set (crime 2017) and variable

   Discuss the shape of each display and what information they reveal about the variable. Tell which is a better display for your data set and why

Explanation / Answer

Mean = Average of all the data Points

Encapsulates all observations but sensitive to outliers

Median = Middle-most value and not sensitive to outliers

In fact helps in better data representation despite the presence of outliers

Mode= Most frequent observation

In this crimes data, it gives a data point which has the most frequency of occurrence

Midrange = (High+Low)/2

The mid-range is rarely used in practical statistical analysis, as it lacks efficiency as an estimator for most distributions of interest, because it ignores all intermediate points

Variance and SD = Measures of dispersion

Talks about how spread out the data is and how far the observations are scattered around the Mean

IQR = Talks about the boundaries beyond which we categorize data points as outliers

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