G and H are mutually exclusive events. * P(G)-0.5 *PCH) = 0.3 E Part (a) Explain
ID: 3062910 • Letter: G
Question
G and H are mutually exclusive events. * P(G)-0.5 *PCH) = 0.3 E Part (a) Explain why the following statement MUST be false: P(HI G)-04 The events are mutually exclusive, which makes P(H AND G) - 0: therefore, PHIG) -o The statement is false because PH | G-an-0.6. P(G) Tofird conditional probability, divide P(G AND H) by PH), which gives 0.5. The events are mutually exclusive, which means they can be added together, and the sum is not 04. Part (b) Find P(H OR G). Part (c) Are G and H independent or dependent events? Explain. O G and H are dependent events because they are mutually exclusive. O There is not engigh information to determine if G and H are independent or dependent events O G and H are independent events because they are mutually exclusive. 0 G and H are dependent events because RG ORH) * 1. Submit Answer Save Progress 16 MacBook Pro FS 2 3 4 5 6Explanation / Answer
Given that, G and H are mutually exclusive events,
P(G) = 0.5
P(H) = 0.3
part a)
If two events A and B are mutually exclusive then
P(A and B)=0
Therefore given statement, P(H | G) = 0.4 is false.
Answer: The events are mutually exclusive , which makes
P(H AND G) = 0 , therefore P(H | G ) = 0
Part b)
P(H OR G) = P(H) + P(G) - P(H AND G)
= 0.5 + 0.3 - 0
P(H OR G) = 0.8
Part c)
G and H are dependent events becaise they are mutually exclusive
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