Researchers measured the data speeds for a particular smartphone carrier at 50 a

Question

Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 74.5 Mbps. The complete list of 50 data speeds has a mean of x= 17.34 Mbps and a standard deviation of s= 20.79 Mbps. a. What is the difference between carrier's highest data speed and the mean of all 50 data speeds? b. How many standard deviations is that [the difference found in part (a)]? c. Convert the carrier's highest data speed to a z score. d. If we consider data speeds that convert to z scores between 2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant? a. The difference is Type an integer or a decimal. Do not round.) b. The difference is (Round to two decimal places as needed.) c. The z score is z (Round to two decimal places as needed) d. The carrier's highest data speed is Mbip. tandard deviations

Explanation / Answer

Solution:

a.What is the difference between carrier's highest data speed and the mean of all 50 data speeds?
=(74.5 - 17.34) = 57.16

b. How many standard deviations is that [the difference found in part (a)]?
= 57.16/20.79
= 2.7493

c. Convert the carrier's highest data speed to a z score.
z = (X - mu)/sd
= (74.5 - 17.34)/20.79
= 2.7493

d. Yes the carrier's highest data speed is significant because it is greater than 2.

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