Researchers measured the data speeds for a particular smartphone carrier at 50 a

Question

Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 77.6 Mbps. The complete list of 50 data speeds has a mean of x overbarequals17.52 Mbps and a standard deviation of sequals21.76 Mbps. a. What is the difference between carrier's highest data speed and the mean of all 50 data speeds? b. How many standard deviations is that [the difference found in part (a)]? c. Convert the carrier's highest data speed to a z score. d. If we consider data speeds that convert to z scores between minus2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?

Explanation / Answer

a. Difference between carrier's highest data speed and the mean of all 50 data speeds = 77.6 - 17.52 = 60.08

b. Standard deviations = 60.80 / 21.76 = 2.76

2.76 standard deviations is that [the difference found in part (a)]

c. Z-score for carrier's highest data speed = ( X - mean ) / Standard deviation = (77.6 - 17.52) / 21.76 = 2.76

d. Since Z -score = 2.76 does not lie between - 2 and 2 , we can say that the carrier's highest data speed is significant.

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