In a poll of 547 human resource professionals, 49.9% said that body piercings an

Question

In a poll of 547 human resource professionals, 49.9% said that body piercings and tattoos were big grooming red flags. Complete parts (a) through (d) below. a) Among the 547 human resource professionals who were surveyed, how many of them said that body piercings and tattoos were big grooming red flags?

273

(Round to the nearest integer as needed.)

b) Construct a 99% confidence interval estimate of the proportion of all human resource professionals believing that body piercings and tattoos are big grooming red flags.

< p <

(Round to three decimal places as needed.)

c) Repeat part (b) using a confidence level of 80%.

< p <

(Round to three decimal places as needed.) Please help this kind of problem still has me confused.

Explanation / Answer

Ok. No problem. Don't get confused. Here; the right answer to the problem, with formulae and calculations:

a) Among the 547 human resource professionals who were surveyed, how many of them said that body piercings and tattoos were big grooming red flags?

273

= n*p where n = total people = 547, p = .499

So, np = 547*.499 = 272.953 or 273

(Round to the nearest integer as needed.)

b) Construct a 99% confidence interval estimate of the proportion of all human resource professionals believing that body piercings and tattoos are big grooming red flags.

99% will have a CI of 2.57

So, 99% CI is p^ +/- Z*SE = .499 +/- 2.57*sqrt(.499*.501/547) = 0.444 to 0.554

0.444<p<0.554

(Round to three decimal places is done as needed.)

c) Repeat part (b) using a confidence level of 80%.

80% will have a CI of 1.28

So, 80% CI is p^ +/- Z*SE = .499 +/- 1.28*sqrt(.499*.501/547) = 0.472 to 0.526

0.472<p< 0.526

(Round to three decimal places is done as needed.)

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