Homework: Homework 9 Save (80% required) 0.4 of 1 pt 20 of 39 (31 complete)W Sco
ID: 3064172 • Letter: H
Question
Homework: Homework 9 Save (80% required) 0.4 of 1 pt 20 of 39 (31 complete)W Score: 65.1... &9.2.28-T Score: E Question Help A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for a random sample of 1079 people age 15 or older, the mean amount of time spent eating or drinking per day is 1.46 hours with a standard deviation of 0.53 hour Complete parts (a) through (d) below. Seiect tne correct cioice veiow ana i in the answer boxes, ir appicapie, in your choice (Type integers or decimals rounded to three decimal places as needed. Use ascending order.) O A. The nutritionist is 90 % confident that the amount of time spent eating or drinking per day for any individual is betweenl and hours B. There is a 90% probability that the mean amount of time spent eating or 0 O c. The nutritionist is 90% confident that the mean amount of time spent eating O D. The requirements for constructing a confidence interval are not satisfied. Click to select and enter your answer(s) and then click Check Answer. drinking per day is between andhous. or drinking per day is between and hours part remaining Check Answer Clear All javascript doExercise(20); 20Explanation / Answer
option C is correct : with fillers are 1.433 and 1.487 Hours
sample mean xbar= 1.46 sample size n= 1079 population std deviation = 0.53 standard errror of mean = x=/n= 0.0161Related Questions
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