Halliday, Fundamentals of Physics, 10e Physics (1201 /1202/2110/2112/21 1 STANDA
ID: 306501 • Letter: H
Question
Halliday, Fundamentals of Physics, 10e Physics (1201 /1202/2110/2112/21 1 STANDARD V?Ew PRINTER VERSION BACK NEX Chapter 09, Problem oss Your answer is partially correct. Try again. A 4.6 kg block with a speed of 4.2 m/s collides with a 9.2 kg block that has a speed of 2.a m/s in the same direction. After the collision, the 9.2 kg block is observed to be traveling in the original direction with a speed of 3.5 m/s. (a) What is the velocity of the 4.6 kg block immediately after the collision? (b) By how much does the total kinetic energy of the system of two blocks change because of the collision? (e) Suppose, instead, that the 9.2 kg block ends up with a speed of 5.6 m/s. What then is the change in the total kinetic energy? (a) Number 2.8 (b) NumberTt.0110913931 (c) NumberExplanation / Answer
b) Initial KE
0.5 * 4.6 * 4.2^2 + 0.5 * 9.2 * 2.8^2 = 76.64 J
final KE
0.5 * 9.2 * 12.25 + 0.5* 4.6 * 7.84 = 74.38 J
loss of KE = 2.26 J (ans)
c) 4.6 * 4.2 + 9.2 * 2.8 = 9.2 * 5.6 + 4.6 * v1
v1 =-1.4
final KE
0.5 * 9.2 * 31.36 + 0.5* 4.6 * 1.96 = 148.76 J
change of KE
= 148.76 - 76.64 = 72.12 J (ans)
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