Halliday, Fundamentals of Physics, 10e Physics I, 11 & 111I Calculus Based (PHYS
ID: 3281547 • Letter: H
Question
Halliday, Fundamentals of Physics, 10e Physics I, 11 & 111I Calculus Based (PHYS 221 & 222 & 22s) Gradebook ORION Downloadable eTextbook nent MESSAGE MY INSIRUCTOR FR The capacitors in the figure are initially uncharged. The capacitances are C When switch S is closed, how many electrons travel down through point b? () In the figure, do the eiectros aet to o i point (e) point c, and (d) point ar (e) In the figure, do the electrons travel up or 1-4.7 , C2-9.6 ur, and C3-13 p, and the battery's potential imrence s v-o· through (a) point a C2 Ci (a) Number 14.26E14 (b) N c) N d) Number 1.4E14 Units No units Unit inits Units No units Units to units 1.4E14 2.86E14 10-34Explanation / Answer
Here,
a) for the net capacitance of the circuit
C1 and C2 are in parallel
C4 = 4.7 + 9.6 = 14.3 uF
Cnet = 14.3 * 13/(14.3 + 13)
Cnet = 6.81 uF
for the charge passing from the a = total charge on circuit
charge passing from the a = 6.81 * 10
charge passing from the a = 68.1 uC
number of electrons passing through a = 68.1 *10^-6/(1.602 *10^-19)
number of electrons passing through a = 4.3 *10^14
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for electron passing from b
electron passing from b = 4.3 *10^14 * 4.7/(4.7 + 9.6)
electron passing from b = 1.41 *10^14
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for the passing from c
electron passing from c = 4.3 *10^14 * 9.6/(4.7 + 9.6)
electron passing from c = 2.89 *10^14
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charge passing through a = charge passing through d
charge passing through d = 4.3 *10^14
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