please write all the rules and reasoning and formulas. how would i approach this

Question

please write all the rules and reasoning and formulas. how would i approach this problem during an exam? what hints? studyin for an exam.

correct answer:

a.) diverging

b.)-8.50 cm

c.)-5.43 cm

d.)right and virtual

e.) 1.09 cm

f.) upright

2. An object 3.00 cm high is placed 15.0 cm in front of a convex spherical mirror with a radius of curvature has a magnitude of 17.0 cm. Circle the correct answer or provide the correct numerical answer for the following parts. a) Is the mirror described above a CONVERGING or DIVERGING mirror? b) What is the focal length of the mirror? c) What is the distance between the image and the mirror (absolute magnitude)? d) Is the image to the RIGHT or LEFT of the mirror and is it REAL or VIRTUAL? e) What is the height of the image (absolute magnitude)? Is the image UPRIGHT or INVERTED?

Explanation / Answer

a). Convex mirror is always diverging in nature.

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b).

Focal length of mirror

f= -8.5 cm

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c).

Object distance,

U= 15 cm

Using mirror formula

1/f= 1/v+1/u

-1/8.5= 1/v+1/15

v= -5.43 cm

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d). It is to the right of mirror. Image formed by convex mirror is always virtual.

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e). Expression of magnification

m= h'/h= v/u

h'= hv/u= 1.086 cm

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f). Virtual image is always upright in nature.

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Do comment in case any doubt..goodluck

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