Can someone help me solve this question correctly? Thank you QUESTION 6-50 Point

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Can someone help me solve this question correctly?

Thank you

QUESTION 6-50 Points A sledder, starting from rest slides down a 1 rough snow. The hill is nearly frictionless, but the coefficient offrictionbet at the bottom is uk- 0.30. How far will the sled slide along the roughch hill At thie bottom of the hill is a long horizontal patch of firiction betvveen the sled and the rough snow 1) Draw a sketch of the sledder sli 2) What locations of the sledder do you ding downhill, represent yhe before/initial and after/final situations. choose as situation 1 and situation 2 ( "before and after" or "initial and final"? Introduce an x-y coordinate system and identify known and to find quantities change in thermal energy during this process? ther any way to relate the thermal energy to the length of the rough patch? Why the other portions 4) Write down the energy-work equation for the process using symbols like K, Ug, Us, AEth. is there any of the path don't matter for change in thermal Energy? 6) Replace the explicit expressions for energies, like "mgy", " mv2", "fk*d", etc. 7) Identify energies that are zero or that don't apply to this process. Does the mass of the sledder cancels out of the work-energy equation? 8) Compute the length of the rough patch. 33.3 m n g h 21.8.lo n Ser on Q.

Explanation / Answer

given height of hill, h = 10 m

rough snow at bottom of hill

riction coefficient , uk = 0.3

1. the drawing is givenalong with the question in the hand drawing

2. location on the top of the hill is locaiton 1, after therough patch when the sled comes to the rest is situation 2

3. let y coordinate be +ve upwards and x coordinate be +ve to the right

4. from work energy equation

mgh = thermal energy

this thermal energy is used up by friction

5. thermal energy = friciton*distance

6. thermal energy = fk*d

7. fk = mg*uk

hence

mgh = mg*uk*d

d = h/uk

d = 10/0.3 = 33.33 m

8. length of rough ppatch = 33.33 m

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