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to an average of 20.3 grams of A recent study found that children who watched a

ID: 3070042 • Letter: T

Question

to an average of 20.3 grams of A recent study found that children who watched a cartoon with food advertising ate, on average, 27.3 grams of crackers as crackers for children who watched a cartoon without food advertising Suppose that there were 56 children in each group, and the sample standard deviation for thos children who watched the food ad was 8 6 grams and the sample standard deviation for those children who did not watch the food ad was 7.8 grams. Complete parts (a) and (b) below children who watched food ads? watch food ads. What are the correct null and alternative hypotheses? O A. Ho:P1-220 1 be the weights of crackers eaten by children who watch food ads and let population 2 be the weights of crackers eaten by children who do not STAT (Round to two decimal places as needed )

Explanation / Answer

a) Option C

Below are the null and alternate hypothesis

H0: mu1 - mu2 <= 0

H1: mu1 - mu2 > 0

b)

n1 = 56

n2 = 56

x1bar = 27.3000

x2bar = 20.3000

sigma1 (s1) = 8.6000

sigma2 (s2) = 7.8000

Sp = sqrt(((n1-1)*s1^2+(n2-1)*s2^2)/(n1+n2-2))

Sp = sqrt((55*8.6^2 + 55*7.8^2)/110)

Sp = 8.2098

Test statistics,

t = (27.3 - 20.3)/(8.2098*sqrt(1/56 + 1/56))

t = 4.5118

p-value = 0.00001

As p-value is less than the significance level, reject the null hypothesis.

c)

x1bar - x2bar = 7.00

SE = 1.5515

CI = 95%

DF = n1+n2-2 = 110

t-value = 1.9818

ME = t*SE = 3.0747

Confidence Interval (x1bar - x2bar) +/- ME

Lower bound = 3.92530

Upper bound = 10.07470

Confidence Interval (3.93 , 10.07 )