to an average of 20.3 grams of A recent study found that children who watched a
ID: 3070042 • Letter: T
Question
to an average of 20.3 grams of A recent study found that children who watched a cartoon with food advertising ate, on average, 27.3 grams of crackers as crackers for children who watched a cartoon without food advertising Suppose that there were 56 children in each group, and the sample standard deviation for thos children who watched the food ad was 8 6 grams and the sample standard deviation for those children who did not watch the food ad was 7.8 grams. Complete parts (a) and (b) below children who watched food ads? watch food ads. What are the correct null and alternative hypotheses? O A. Ho:P1-220 1 be the weights of crackers eaten by children who watch food ads and let population 2 be the weights of crackers eaten by children who do not STAT (Round to two decimal places as needed )Explanation / Answer
a) Option C
Below are the null and alternate hypothesis
H0: mu1 - mu2 <= 0
H1: mu1 - mu2 > 0
b)
n1 = 56
n2 = 56
x1bar = 27.3000
x2bar = 20.3000
sigma1 (s1) = 8.6000
sigma2 (s2) = 7.8000
Sp = sqrt(((n1-1)*s1^2+(n2-1)*s2^2)/(n1+n2-2))
Sp = sqrt((55*8.6^2 + 55*7.8^2)/110)
Sp = 8.2098
Test statistics,
t = (27.3 - 20.3)/(8.2098*sqrt(1/56 + 1/56))
t = 4.5118
p-value = 0.00001
As p-value is less than the significance level, reject the null hypothesis.
c)
x1bar - x2bar = 7.00
SE = 1.5515
CI = 95%
DF = n1+n2-2 = 110
t-value = 1.9818
ME = t*SE = 3.0747
Confidence Interval (x1bar - x2bar) +/- ME
Lower bound = 3.92530
Upper bound = 10.07470
Confidence Interval (3.93 , 10.07 )
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