We obtain the marginal probability P(E) by adding these four joint probabili- ti

Question

We obtain the marginal probability P(E) by adding these four joint probabili- ties as follows: 0881+0597 +.1289 +.1667 ,4434 result, as expected, is the same as the one obtained by using the marginal total for Early as the numerator and the total number of subjects as the denominatr The SES In a study of violent victimization of women and men. Porcerelli et al. (A-2) collected information from 679 metropolitan Detroit area. Patients filled out a health history questionnaire that included a question about victimization. The following table shows the sample subjects cross-classified by sex and the type of violent victimization reported. The victimization categories are defined as no vi partner victimization (and not by others), victimization by persons other than partners( family members, or strangers), and those who reported multiple victimization women and 345 men aged 18 to 64 years at several family practice centers in the friends, No Victimization Partners Nonpartners Multiple Victimization Total 679 345 Women Men 611 308 34 10 16 17 18 10 Total 919 28 1024 Source: Data provided courtesy of John H. Porcerelli. Ph. D. Rosemary Cogan. Ph.D. (a) Suppose we pick a subject at random from this group. What is the probability that this subject will be a woman?O (b) What do we call the probability calculated in part a? (c) Show how to calculate the probability asked for in part a by two additional methods. Mar n part a? 33670663

Explanation / Answer

a|)P(women) =679/1024 =0.6631 (as out of 1024 people there are 679 women)

b)this is called marginal as is nt confditioned on voilent victimization reported

c)

frist method:P(women)=1-P(men)=1-345/1024=1-0.3369 =0.6631

second method:

P(women)=P(women and no victimization)+P(women and partners)+P(women and nonpartners)+P(women and multiple  victimization)

=(611/1024)+(34/1024)+(16/1024)+(18/1024)=0.6631

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