The 40th percentile is between per capita operating expenditures of s between pe
ID: 3071838 • Letter: T
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The 40th percentile is between per capita operating expenditures of s between per capita operating expenditures ofSlc Question Details Suppose that the distribution of weekly water usage for single-family homes in a particular city is mound shaped and approximately symmetric. The mean is 1,500 gallons, and the standard deviation is 200 gallons. (Use the Empirical Rule.) PeckStat2 3..059. [401967 (a) What is the approximate value (in gal) of the 16th percentile? gal (b) What is the approximate value (in gal) of the median? gal (c) What is the approximate value (in gal) of the 84th percentile? gal Question Details PeckStat2 3..061. [401% Suppose that the distribution of scores on an exam is mound shaped and approximately symmetric. The exam scores have mean of 100 and the 16th percentile is 75. (Use the Empirical Rule.) (a) What is the 84th percentile? (b) What is the approximate value of the standard deviation of exam scores? (c) What is the z-score for an exam score of 907 (d) What percentile corresponds to an exam score of 150? Since a score of 25 is Select below the mean, that corresponds to a percentile of Therefore, there were Select..scores below 25 (e) Do you think there were many scores below 25? Explain. Assignment Details Nante (AID) Chapter 3 (13335363) Feedback Settings Before due date n(cet3 htmExplanation / Answer
Mean = 1500
S.D. = 200
a)
16th percentile
From Z score table z score value at p-value at 0.16
Z = - 0.994
Z = (X - ) /
- 0.994 = (X - 1500) / 200
-0.994*200 +1500 = X
X = 1301.2
b)
Mean =median in symmetric mount shaped curve
Median = 1500
c)
84th percentile
From Z score table z score value at p-value at 0.84
Z = 0.994
Z = (X - ) /
0.994 = (X - 1500) / 200
0.994*200 +1500 = X
X = 1698.8
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