A 2014 Pew study found that the average US Facebook user has 338 friends. The st

Question

A 2014 Pew study found that the average US Facebook user has 338 friends. The study also found that the median US Facebook user has 200 friends. What does this imply about the distribution of the variable "number of Facebook friends"?
(You have two attempts for this problem, and five attempts each for the remaining problems)

The distribution is right skewedThe distribution is bimodal    The distribution is approximately Q3The distribution is symmetricalThe distribution is left skewedThe distribution is normalThe distribution is trending

Please explain answer!!

3. +-125 points My Notes A 2014 Pew study found that the average US Facebook user has 338 friends. The study also found that the median US Facebook user has 200 friends. What does this imply about the distribution of the variable "number of Facebook friends"? (You have two attempts for this problem, and five attempts each for the remaining problems) The distribution is right skewed O The distribution is bimodal O The distribution is approximately Q3 O The distribution is symmetrical O The distribution is left skewed O The distribution is normal O The distribution is trending The Pew study did not report a standard deviation, but given the number of Facebook friends is highly variable, let's suppose that the standard deviation is 206. Let's also suppose that 338 and 206 are population values (they aren't, but we don't know the true population values so this is the best we can do). (Use 3 decimal place precision for parts a., b., and c.) a. If we randomly sample 116 Facebook users, what is the probability that the mean number of friends will be less than 346? b. If we randomly sample 114 Facebook users, what is the probability that the mean number of friends will be less than 313? c. If we randomly sample 600 Facebook users, what is the probability that the mean number of friends will be greater than 346? (Round to the nearest integer for parts d. and e.) d. If we repeatedly take samples of n=600 Facebook users and construct a sampling distribution of mean number of friends, we should expect that 95% of sample means will lie between and e. The 75th percentile of the sampling distribution of mean number of friends, from samples of size n=116, is: Submit Answer Save Progress Practice Another Version

Explanation / Answer

a)

( please try 0.662 if this comes wrong)

b)

( please try 0.098 if this comes wrong)

c)

d)

for 95% middle value z score =-/+1.96

hence it will lie =mean -/+ z*std error = 338-/+1.96*8.4099 =321.52 and 354.48~ 322 and 354

e)

for 75th percentile ; z =0.67

mean number of friends =338+0.67*19.266 =351

for normal distribution z score =(X-)/ here mean=       = 338 std deviation   == 206.000 sample size       =n= 116 std error=x=/n= 19.1266

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