ln engineering fium offeus testing for electrical paducts. Cuvrently they ave te
ID: 3072236 • Letter: L
Question
ln engineering fium offeus testing for electrical paducts. Cuvrently they ave testing a type af campact pertakle music playet. They andomly select a number af the music player and canduct a series of tests and compute an overall score for each unit 6ased upon the wults of tfie testing 0utine. They determine that the test scores ave noxmally distvibuted with a mean af 310 and a variance of 1,270. l unit is deemed fauilty if it scares belouu 250. Find the prebakility af a tandom unit being falty- Çive your answer as a decimal ta 2 decimal places 3.ebabilit,- l graup af mutual funds earned varying annual rates af retuun in the last year. Jhese vates af etuvn aue nornally distributed with a mean of 8 and a standand dew tien of 18% Cne mutua und in this group managed to ea in ute a etuon that was deuAfe that of this groups average that yean. This perfermance uould put the fund in the top of those funds in that yeat. Calculate X« Çive your answer to 1 decimal place. Hou are the ceach af a basketball team that is cuvrently looking fox new playets. Cne of the citeria fer selecticn as a player is that the person muust te above a particular height. Jdeally, you want yaur neat player to be as tall as passible. Jtowevet, yau da nat want to wle out any potential playes by making the cut-off heigfit toa stvict. au decide that accepting players within the top 2.5% height brach t wdl be seasonable for your team. assume tfiat the height of all people fallous a rue anal distribution with mean of 68.6 in and a stan and deviatien of38 in. Calculate the cut-off height (e) that ensures only peaple within the tap 2.57% heigfht &racket ave allawed inta the team. Çive yaur answer in inches te the neavest inch.Explanation / Answer
#1.
mean = 310
sd = sqrt(1270) = 35.6371
P(X < 250)
= P(z < (250 - 310)/35.6371)
= P(z < -1.6836)
= 0.0461
Probability = 0.0461
#2.
mean = 8
sd = 18
P(X > 16)
= P(z > (16 - 8)/18)
= P(z > 0.4444)
= 0.3284
X% = 32.84%
#3.
mean = 68.6, sd = 3.8
for top 2.5%, z-value = 1.96
x = 68.6 + 1.96*3.8 = 76.0480
Hence cut-off height is 76 inches
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