Each year a company selects a number of employees for a management training prog

Question

Each year a company selects a number of employees for a management training program. On average, 40 percent of those sent complete the program. Out of the 41 people sent, what is the probability that exactly 8 complete the program? a) 0.0469 b) 0.0044 )0.104 0.2029 0.0029 None of the above Question9 Review Later Each year a company selects a number of employees for a management training program. On average, 40 percent of those sent complete the program. Out of the 29 people sent, what is the probability that 7 or more complete the program? a) 0.1569 b 0.023.3 c)0.056 )0.9766 e) 009430 f) ONone of the above

Explanation / Answer

a) n = 41

P = 0.40

It is a binomial distribution.

P(X = x) = nCx * p^x * (1 - p)^(n - x)

P(X = 8) = 41C8 * (0.4)^8 * (0.6)^33 = 0.00299

Option - e is correct.

b) n = 29

P = 0.40

P(X > 7) = 1 - P(X < 7)

= 1 - (P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6))

= 1 - (29C0 * (0.4)^0 * (0.6)^29 + 29C1 * (0.4)^1 * (0.6)^28 + 29C2 * (0.4)^2 * (0.6)^27 + 29C3 * (0.4)^3 * (0.6)^26 + 29C4 * (0.4)^4 * (0.6)^25 + 29C5 * (0.4)^5 * (0.6)^24 + 29C6 * (0.4)^6 * (0.6)^23)

= 1 - 0.0233

= 0.9767

Option - d is correct.

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