fari File Edit View History Bookmarks Window Help i webassign.net Stat 301 Modul
ID: 3073245 • Letter: F
Question
fari File Edit View History Bookmarks Window Help i webassign.net Stat 301 Module 4 Honework Stat 301 Module 4 Honework A 2014 Pew study found that the average US Facebook user has 338 friends. The study also found that the median US Facebook user ha does this imply about the distribution of the variable "number of Facebook friends"? You have two attempts for this problem, and five attempts each for the remaining problems) s 200 friends. what O The distribution is bimodal O The distribution is normal O The distribution is trending O The distribution is symmetrical O The distribution is right skewed O The distribution is approximately Q3 O The distribution is left skewed The Pew study did not report a standard deviation, but given the number of Facebook friends is highly variable, let's suppose that the standard devilation is (Use 3 decimal place precision for parts a, b., and c.) a. If we randomly sample 120 Facebook users, what is the probability that the mean number of friends will be less than 346 087 b. If we randomly sample 118 Facebook users, what is the probability that the mean number of friends will be less than 3177 00062 c. If we randomly sample 600 Facebook users, what is the probability that the mean number of friends will be greater than 3467 0.1530 (Round to the nearest integer for parts d. and e.) d. If we repeatedly take samples of n-600 Facebook users and construct suppose that 338 and 198 are population values (they aren't, but we don't know the true population values so this is the best we can do) a sampling distribution of mean number of friends, we should expect that 95% of sample means will lie between 338 x and 158 e. The 75th percentile of the sampling distribution of mean number of friends, from samples of size n-120, is: 3soExplanation / Answer
a)
b)
c)
d)
for middle 95% values ; crtical z =1.96
hence number =mean-/+z*std deviation =322 and 354
for normal distribution z score =(X-)/ here mean= = 338 std deviation == 198.000 sample size =n= 120 std error=x=/n= 18.0748Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.