6x 2 -10x-4 2(3x 2 -5x-2) I then think, product of factor 2(3)=6are 1,-6 -1,6 3,
ID: 3092189 • Letter: 6
Question
6x2-10x-4 2(3x2-5x-2) I then think, product of factor 2(3)=6are 1,-6 -1,6 3,-2 and -3,2 then I ask, which of thesefactors when added, will give me -5. I then conclude 1,-6 willfulfill this so I proceed with (3x-6)(x+1). after this I am lost. I have the solution that was in the backof the book, but I cannot get pass the above step on any of theproblems I have, even when I switch the signs. Ans.2(3x+1)(x-2) 6x2-10x-4 2(3x2-5x-2) I then think, product of factor 2(3)=6are 1,-6 -1,6 3,-2 and -3,2 then I ask, which of thesefactors when added, will give me -5. I then conclude 1,-6 willfulfill this so I proceed with (3x-6)(x+1). after this I am lost. I have the solution that was in the backof the book, but I cannot get pass the above step on any of theproblems I have, even when I switch the signs. Ans.2(3x+1)(x-2)Explanation / Answer
1) Factor out anything you can to simplifiy thepoynomial expression
2(3x^2-5x-2) = 6x^2-10x-4
2) Now that your polynomial is simplified, begin thefactoring
temporarily ignore the "2"....fornow So, just try to factor(3x^2-5x-2)
-Use the trial and error method tofactor
first, you know that your first terms inthe factors will have to be 3 and 1, obviously second, you know that the second termswill have to be 2 and 1 third, you know that one of the secondterms will be negative
Using this knowledge, you can easily perform trial and erroruntil you arrive at the correct factor terms of
(3x+1) and (x-2)
Now reinsert the "2" you had "ignored" in the beginning toarrive at you final answer of
2(3x+1)(x-2)
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