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6:54 PM drive.google.com mens shoe store rome-Google Searchisscm-fa17-mt1 exam.p

ID: 3328685 • Letter: 6

Question

6:54 PM drive.google.com mens shoe store rome-Google Searchisscm-fa17-mt1 exam.pd Goo.. you must get 8 out of 50 numbers co.. iPad 35% . ways tne positions can be riea oy tnese appiicants. Hin: tnis is simuar to tne nursing review problem.) A. 2,432,902,008,176,640,000 B. 20,922,789,888,000 C. 116,280 D. 101,370,917,007,360,000 36·There are 9 multiple-choice questions on an exam, each with 4 possible answers. Determine the number of possible answer sequences for the 9 questions (meaning A, A, B, C... or A, A, B, C., etc.). A. 214,566 B. 262,144 C. 6,561 37. You want to get rich without working so you play the lottery. You must get 8 correct out of 50 numbers. What are your odds of winning? A. 0.00000019% B 00000000000046% C. 0.0000000052% D. 10% 38. The permutations formula is (n!nr)!) and the combinations formula is (n(n-r)) correct? Which of the following statements is A. Permutation is used when a member of the larger group (n) may hold any of the positions in the smaller group (r). Combinations is used when a member of the larger group (n) can only hold one position in the smaller group (r) B. Permutation is used when a member of the larger group (n) may hold only one of C. Permutations is used when selecting members of a team from a larger group. D. Permutations is used when selecting members of a committee (where all persons the positions in the smaller group (r). Combinations is used when a member of the larger group (n) can hold any position in the smaller group (r). Combinations is used when selecting members for a committee (where all person:s are of equal rank) from a larger group. are of equal rank) from a larger group. Combinations is used when selecting members for a team from a larger group A and C Band D E. F.

Explanation / Answer

37) Number of ways in which 8 numbers can be chosen from 50 = 50C8

nCr = n! / (r! x (n-r)!)

So, 50C8 = 50! / (8! x 42!)

= 536878650

Odds of winning = 1 / 536878650

= 0.0000000019

= 0.00000019% (option A)