determine the equation in standard form for the line passingthrough (4,2) and pa

Question

determine the equation in standard form for the line passingthrough (4,2) and parallel to the horizontal line through(1,-2)

my solution - step 1
since the line is horizontal therefore y = k
y = -2
y + 2 = 0

step 2
since both lines are parallel therefore m1 =m2 and from step 1 we know that slope is 0 since theline is horizontal therefore use point slope form:
y - y0 = m(x - x0)
y - 2 = 0(x - 4)
y -2 = 0 >>>>solution

okay my solution is correct but am i using the right approach ormethod? or am i making things too complicated... because the answerin the book is much simpler. which is:

so the line is horizontal through (4,2) and the equation is y = 2,in standard form the equation is
y - 2 = 0

Explanation / Answer

You do not need to go through all of those steps because the line is horizontal, meaning there is no slope, and no x value. To set up the equation for the line, all you need is the y coordinate since the line will be a y= (horizontal). Again, because there is no slope all you need to do is set y equal to the y coordinate.

Related Questions

Navigate

• Browse (All)
• Browse D
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.