Table 5.2 x 0 1 2 3 4 5 6 7 8 9 f(x) -10 -7 4 29 74 145 248 389 574 809 g(x) -6

Question

Table 5.2
x 0 1 2 3 4 5
6
7
8
9
f(x) -10
-7
4
29 74
145
248
389
574
809
g(x)
-6 -7
6 33
74 129
198
281
378
489

(a) Using table 5.2, evaluate:    
       (i)    f(x) for x = 6
      (ii)     f(5) -3
     (iii)     f(5 - 3)
     (iv)     g(x) + 6 forx = 2
      (v)     g(x + 6)for x = 2
     (vi)     3g(x) for x =0
    (vii)     f(3x) for x =2
   (viii)     f(x) - f(2) for x =8
     (ix)     g(x + 1) -g(x) for x = 1

(b) solve
       (i)    g(x) =6
      (ii)    f(x) =574
     (iii)    g(x) = 281

(c) The values in the table were obtained using the formulas f(x) =x3 + x2 + x - 10 and
g(x) = 7x2 - 8x - 6. Use the table to find twosolutions to the equation x3 + x2 + x - 10 =7x2 -8x -6.

x 0 1 2 3 4 5
6
7
8
9
f(x) -10
-7
4
29 74
145
248
389
574
809
g(x)
-6 -7
6 33
74 129
198
281
378
489

Explanation / Answer

*** To solve these problems, when asked for f(x) where x = 0(or any other number). Look at the values for f(x) and then findthe f(x) value (or g(x)) at the given x value. For istance f(0) =-10. This is the associated f(x) value where the x = 0. Same wayfor g(x). So g(x) where x=0 is same as asking for g(0) which is -6.If they say find g(3) - 2, you find g(3) and then just subtract 2from that number.    In part (b), they give you a g(x) or f(x)value and you find the x-value that's assciated with that. so ifasked, find g(x) = -6, we would look to see what x-value isassociated with the g(x) that is -6, this is x = 0. (i)      (f(6) = 248)
     (ii)       =142
    (iii)      =4
     (iv)      =12
     (v)       =378
    (vi)        = -18
    (vii)       =248
   (viii)     = 570
     (ix)     = 13 Part 2: (i) x = 2 (ii) x = 8 (ii) x = 7 Part 3: Find two places where g(x) = f(x) at x = 1 and x = 4 Hope that helps!!! Hope that helps!!!

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