Hi, I am wondering if someone could check my work to see if Iworked this problem

Question

Hi, I am wondering if someone could check my work to see if Iworked this problem correctly? An object is projected vertically upward with an initialvelocity of v0 ft/sec, and its distance s(t) in feetabove the ground after t seconds is given by the formula s(t)= -16t2 + v0t A. If the object hits the ground after 12 seconds, fimdits initial velocity v0 B. Find its maximum distance above the ground. Part A. I figure first since distance in feet above ground is s(t)then s(t) = ground or 0 second (t) = 12 since it represents time 0 = -16(12)2 +v0(12) 2304 = 12v0 So I am saying then that the initial velocity is 192 ft/sec? next part not quit sure how this should be stated so usingparabola terms, s(t) = -16(6)2 + 192(6) 576 = Maximum Height above the ground? Did I work this correctlyor did I make a mistake along theway? Thanks, Jeff

Explanation / Answer

You worked this perfectly. When it hits the ground s(t) = 0 so you set up the equationcorrectly for part A Projectile is at its highest point at the vertex which ishalfway between lift off and touch down or in this case 6seconds

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