The Equation of a circle of a circle is x^2 + y^2 = 64 (a) What is the radius of

Question

The Equation of a circle of a circle is x^2 + y^2 = 64 (a) What is the radius of this circle? (b) Do the points Q (-4, 7) and R (0, -8) lie on the circle?If not, where are the points in relation to the circle? Justifyyour answer algebraiclly. (c) Write a mapping rule to express the circle as atransformation of the unit circle. Here is what I got I need confromation that this isright: (a) (x-h)^2 + (x-k)^2 64 = r^2 8 = r (b) Point (-4, 7) -4^2 + 7^2 = 64 16 + 49 = 64 65 is not equal to 64 therefore (-4, 7) does not lie on thecircle. Point (0, -8) 0^2 + -8^2 = 64 64= 64 Point (0, -8) lies on the circle. (c) x^2 + y^2 = 64 y^2 = (x+8)^2 (x,y) --> (x + 8, y) Are these right? The Equation of a circle of a circle is x^2 + y^2 = 64 (a) What is the radius of this circle? (b) Do the points Q (-4, 7) and R (0, -8) lie on the circle?If not, where are the points in relation to the circle? Justifyyour answer algebraiclly. (c) Write a mapping rule to express the circle as atransformation of the unit circle. Here is what I got I need confromation that this isright: (a) (x-h)^2 + (x-k)^2 64 = r^2 8 = r (b) Point (-4, 7) -4^2 + 7^2 = 64 16 + 49 = 64 65 is not equal to 64 therefore (-4, 7) does not lie on thecircle. Point (0, -8) 0^2 + -8^2 = 64 64= 64 Point (0, -8) lies on the circle. (c) x^2 + y^2 = 64 y^2 = (x+8)^2 (x,y) --> (x + 8, y) Are these right?

Explanation / Answer

As far as I can see, all of your answers are indeed correct.  Good work.

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