The product of two consecutive odd integers is 143. Develop the trinomial equati

Question

The product of two consecutive odd integers is 143. Develop the trinomial equation, solve the equation, and find the two consecutive integers? a) -13, 11 b) -11, 13 c) 12, 12 d) -11, -13 Find two consecutive integers such that the product of 2 times the first and the second is 364? Develop the trinomial equation, solve the equation, and find the two consecutive integers? a) -14, -13 b) -13, 14 c) 26, 14 d) -14, 13 Find the LCD and use that to find the numerator?: 3/x - 2 - 6/x^2 - 4 = ?/LCD a) -3 b) 3x c) 3x + 6 d) 3x+12

Explanation / Answer

65.

3/(x - 2) - 6/(x^2 - 4)

= 3/(x - 2) - 6/[(x-2)*(x+2)]

= (3*(x+2) - 6)/[(x-2)*(x+2)]

= (3x + 6 - 6)/[(x-2)*(x+2)]

= 3x/[(x-2)*(x+2)]

numerator = 3x

Correct option is B.

64.

suppose two integers are

x and (x+1)

Now given that

2*x*(x+1) = 364

x^2 + x = 182

x^2 + x - 182 = 0

x^2 + 14x - 13x - 182 = 0

(x + 14)*(x - 13) = 0

x = -14 and x = 13

Integers can be -14 and -13

Or 13 and 14

from given options correct option is A.

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