<p><img src=\"https://media.cheggcdn.com/media%2F088%2F0886aa2a-90e5-445f-abe8-8

Question

<p><img src="https://media.cheggcdn.com/media%2F088%2F0886aa2a-90e5-445f-abe8-8d9f99f083c3%2Fphp9HDz5h.png" data-mce-src="https://media.cheggcdn.com/media%2F088%2F0886aa2a-90e5-445f-abe8-8d9f99f083c3%2Fphp9HDz5h.png"></p>

Explanation / Answer

1) limx->2 (2x+3) let f(x) = 2x+3 limx->2 cf(x) = climx->2 f(x) let c = 1 limx->2 f(x) = 7 =1 x 7 = 7 2)lim x->3 f(x) = 5 a)lim x->3 (f(x)+7) from law limx->3 (f(x)+c) = limx->3 f(x) +c =f(x)+ 7 =5 +7 =5+7 = 12 b) lim x->3 (7f(x)) from law limx->3 cf(x) = climx->3 f(x) =7(5) = 35 c) lim x->3 (7/f(x)) from law limx->3 c/f(x) = c(limx->3 1/f(x)) =7/5 d) lim x->3 ((x+7)/(f(x)-3) from law limx->3 (x+c1)/(f(x)-c2) = (x+c1)/(f(x)-c2) (3+7)/(5-3) = 10/2 = 5

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