If a colony of bacteria increases by 35% 12 hours, a) Find the value of k (const

Question

If a colony of bacteria increases by 35% 12 hours, a) Find the value of k (constant) round to 4 decimal places b) Find the doubling time in hours (whole number)

Explanation / Answer

Dear Student Thank you for using Chegg !! Given That the population of acteria increases by 35% in 12 hours => General form of bacteria population at any time t should be P(t) = P(0) * (e)^(kt) After 12 hours, P(12) = 1.35 P(0) 1.35 P(0) = P(0) * (e)^(k12) 1.35 = (e)^(k12) Taking natural log both sides 0.300104592 = 12k k = 0.025008716 Hence value of k is = 0.025 Solution b) Doubling time => P(t) = 2P(0) 2P(0) = P(0) * e^ (0.025*t) 2 = e^ (0.025*t) Taking natural log both sdes 0.693147181 = 0.025t t = 27.72588722 Time to double = 27.7 hours Whole Number ~28 Hours Solution

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.